The Fifteenth Term Of An Arithmetic Sequence Is 29 And The 27th Term Is 47 Find The First Term And The Common Difference
The fifteenth term of an arithmetic sequence is 29 and the 27th term is 47 find the first term and the common difference
Answer:
3/2=d
8=a1
Step-by-step explanation:
a15=29
n=15
29=a1+(15-1)d
29=a1+14d
a27=47
47=a1+(27-1)d
47=a1+26d
-(29=a1+14d)
+ 47=a1+26d
= 18=12d
18/12 =12d/12
3/2= D
47=a1+26(3/2)
47=a1+(13×3)
47=a1+39
47-39=a1
8=a1
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