The Fifteenth Term Of An Arithmetic Sequence Is 29 And The 27th Term Is 47 Find The First Term And The Common Difference

The fifteenth term of an arithmetic sequence is 29 and the 27th term is 47 find the first term and the common difference

 

Answer:

3/2=d

8=a1

Step-by-step explanation:

a15=29

n=15

29=a1+(15-1)d

29=a1+14d

a27=47

47=a1+(27-1)d

47=a1+26d

-(29=a1+14d)

+ 47=a1+26d

= 18=12d

18/12 =12d/12

3/2= D

47=a1+26(3/2)

47=a1+(13×3)

47=a1+39

47-39=a1

8=a1